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jacamron
04.07.2019 •
Mathematics
Given events g and h: p(g) = 0.46; p(h) = 0.26; p(h and g) = 0.13 a)find the probability of the complement of event (h and g). b)find the probability of the complement of event (h or g).
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Ответ:
We are given
P(G)=0.46
P(H)=0.26
P(H∩G)=0.13
(a)
we know that
the probability of the complement of event (H AND G) is
=1-P(H∩G)
so, we can plug value
the probability of the complement of event (H AND G) is
=1-0.13
=0.87Answer
(b)
the probability of the complement of event (H OR G) is
=1-P(H∪G)
so, firstly we will find P(H∪G)
P(H∪G)=P(H)+P(G)-P(H∩G)
now, we can plug value
P(H∪G)=0.26+0.46-0.13
P(H∪G)=0.59
So,
the probability of the complement of event (H OR G) is
=1-0.59
=0.41Answer
Ответ:
2+5-(3-3)
2+5-0
7-0
7
hope this helps