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idk9329
17.03.2020 •
Mathematics
Given rectangle ABCD below,
a. Find the measure of the angles labeled below.
b. If the length of AB=3x–21, DC=34, BC=4y+32, and AD=62, find the values of x and y.
c. Find the perimeter and area of rectangle ABCD.
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Ответ:
Step-by-step explanation:
a) no angles are described or shown
__
b) Opposite sides are the same length, so we have ...
3x -21 = 34
3x = 55 . . . . . . . add 21
x = 55/3 = 18 1/3 . . . . . divide by 3
and
4y +32 = 62
4y = 30 . . . . . . . . subtract 32
y = 15/2 = 7 1/2 . . . . divide by 4
__
c) The perimeter is the sum of the side lengths, so is ...
P = 2(L+W) = 2(62 +34) = 192 . . . units
The area is the product of adjacent side lengths, so is ...
A = LW = 62·34 = 2108 . . . square units
Ответ:
For example:
2(1 + 3)
2(1) + 2(3)
2 + 6
8.
Now that we've broken down what we're dealing with, let's try to solve.
-3(b + 19) = -12
-3(b) + -3(19) = -12
-3b -57 = -12
Add 57 to both sides to get -3b by itself.
-57 + 57 = 0
-12 + 57 = 45
-3b = 45
Divide both sides by -3 to solve for b.
-3b / -3 = b
45 / -3 = -15
b = -15
I hope this helps! PM me if you need help understanding.