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Jasminehenry123
07.11.2020 •
Mathematics
Grade 11 Algebra 2
Can any one please help me with this Algebra 2 math problem. Soon as possible!
Write an equation in slope-intercept form for the line that passes through (–2, 1) and is parallel to the line whose equation is 3x + 2y = 6.
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Ответ:
y=-3/2x-2
Step-by-step explanation:
simplify 3x+2y=6 first
-3x. -3x
2y= -3x+6
Divide by 2
y= -3/2x+3
since it's parallel you would use the same slope
slope= -3/2x
Now you need to find b (x-intercept)
point (-2,1)=(x,y) use this to plug into y=mx+b
=
(1)=-3/2(-2)+b (simplify)
1 = 3+b
-3 -3
-2= b
so put it together and get
y=-3/2x-2
Ответ:
2x + (5x - 10) = 180
2x + 5x - 10 = 180
7x - 10 = 180
+ 10 +10
7x = 190
7 7
x = 27¹/₇