Helpppppppp here plz

x + x+12 + 3(x+12) = 123

x = 15

Step-by-step explanation:

Jamil : x

Kiera : x+12

Luther : 3 ( x+12)

x + x+12 + 3(x+12) = 123

Distribute

x + x+12 + 3x+36 = 123

Combine like terms

5x+ 48 = 123

Subtract 48 from each side

5x+48-48 = 123-48

5x =75

Divide by 5

5x/5 = 75/5

x = 15

Equation:

123 = x + 12 + x + 3(12 + x)

Solution:

x = 15

Step-by-step explanation:

Jamil: x

Kiera: 12 + x

Luther: 3(12 + x)

Total: 123 badges

Equation:

123 = x + 12 + x + 3(12 + x)

Solve:

123 = x + 12 + x + 3(12 + x)

123 = x + 12 + x + 36 + 3x

123 = 5x + 48

-48           -48

75 = 5x

/5     /5

15 = x

Therefore, the value of x is 15.

The first expression, 12C3, is the right answer. There is no limitation saying that the team must be made up of one student from each year level. Furthermore, no distinction has been made among the three players (no assignments of Boards 1, 2, or 3), as the question just asks how many different groups. Since order does not matter, this is a combination. (If order mattered, this would be a permutation).