Mathematics: ???????????????helppppppppp

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lizbeth696

17.10.2021

$27 = 3 \cdot 9 = 3 \cdot 3 \cdot 3 = 3^3$

Step-by-step explanation:

In general, let n be a natural number, and p_1, p_2, ..., p_k be a set of its prime factors, each with a multiplicity k_1, k_2, ..., k_k (multiplicity being the "number of times a given prime shows up as a factor"). Then every number can be written as a product in an exponential form:

$n = p_1^{k_1}\cdot p_2^{k_2}\cdot\cdot\cdot p_k^{k_k}$

In the example of 27, the p_1=3 and k_1 = 3.

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