Hippocrates magazine states that 35 percent of all americans take multiple vitamins regularly. suppose a researcher surveyed 750 people to test this claim and found that 296 did regularly take a multiple vitamin. is this sufficient evidence to conclude that the actual percentage is different from 35% at the 5% significance level?
select the [p-value, decision to reject (rh0) or failure to reject (frh0)].

a) [p-value = 0.060, frh0]

b) [p-value = 0.010, frh0]

c) [p-value = 0.010, rh0]

d) [p-value = 0.005, rh0]

e) [p-value = 0.005, frh0

p value = 0.005 for right tailed

Reject H0

Step-by-step explanation:

Given that Hippocrates magazine states that 35 percent of all Americans take multiple vitamins regularly.

Persons surveyed = 750

Of those survived no of persons who took multiple vitamin = 296

Sample proportion = p =0.395

q =1-p = 0.605

(Two tailed test)

Assuming H0 is true standard error =

p difference = 0.045

Test statistic =

p value = 0.005 for right tailed

Reject H0

Option d is right

I think its 2 F every hour.

Step-by-step explanation:

The time between 5am and 11am is 6 hours, so 12 divided by 6 is 2.