Mathematics: How can 1/4x-3=1/2x+8 be set up as a system of equations? ? a) 4y+4x=-12 2y+2x=16 b) 4y-x=-12 2y-x=16 c) 4y+x=-12 2y+x=16 d) 4y-4x=-12 2y-2x=16

idkStep-by-step explanation:...

How can 1/4x-3=1/2x+8 be set up as a system of equations?

freemankellie

12.03.2022

we are given

$\frac{1}{4} x-3=\frac{1}{2} x+8$

Let's assume it is equal to y

$\frac{1}{4} x-3=\frac{1}{2} x+8=y$

so, we can write

$y=\frac{1}{4} x-3$

we can multiply both sides by 4

$4y=4*\frac{1}{4} x-4*3$

4y=x-12

4y-x=-12

so, we got

first equation is

4y-x=-12

now, we can find second equation

$y=\frac{1}{2} x+8$

we can multiply both sides by 2

$2y=2*\frac{1}{2} x+2*8$

2y= x+16

2y-x=16

so, we got

system of equations as

2y-x=16

[tex] 4y-x=-12 [/tex

so, option-B..............Answer

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