How do you graph this
y-2x=0
y=4x+3

Step-by-step explanation:

those are 2 lines, and to graph them find 2 points for each to draw a line trough them

line 1

y-2x=0 so y=2x

pick any value for x

(x=1, y=2*1=2), (x=3, y=2*3=6)

Draw a line trough points (1,2) and (3,6)

line 2

y=4x+3

(x=1, y=4*1+3=7), (x= -1, y= 4(-1)+3= -1)

Draw a line trough points (1,7) and (-1, -1)

Answer

(with step-by-step explanation):

[Find first the value of the 5th term.]

an = a1(r)^n-1

A5 = 2(3)^5-1 = 2(3)⁴ = 2(81) = 162

[Use the formula in finding sum of terms in Geometric Sequence]

Sn = [a1 - an(r)] / 1 - r

[Substitute the given values]

S5 = [2 - 162(3)] / 1 - 3

= 2-486 / -2 = -484/-2 = 242

• Therefore, the answer is Letter B, 242.

This question was already answered by another so i copied it so you would not have to go to that question. :)