How far did the car travel during the 10 sec trip? Position (km) Time (sec) 5 0 8 2 10 4 16 6 20 8 20 10 Answer choices- 10 km 15 km 20 km (this is the one I chose) 79 km

15 km

Step-by-step explanation:

Given the table:

To find:

The distance traveled by the car.

Solution:

Here, we are given the position of the car after an interval of 2 seconds.

We are not given the distance traveled.

If the distance traveled would have been given, then distance traveled by car = Sum of all the values = 5 + 8 + 10 + 16 + 20 + 20 = 79 km

Then the answer would have been 79 km.

As, we are given the position here, so the distance traveled will be equal to final position minus the initial position.

Distance traveled in 10 seconds = Position at 10 seconds - Position at 0 seconds = 20 - 5 = 15 km

The relationship between <7 and <8 can be said to be vertically opposite angles. They are equal to one another and formed by the intersection of two straight lines. i.e. the intersection of lines C and D.

The special angles created by the intersection of lines C and D can be used to solve for y because they all are inter woven and connected to one another either supplemtarily or by being vertically opposite angles.

5y - 29 = 3y + 19( vertically opposite angles)

5y - 3y = 19 + 29

2y = 48

y = 48/2

= 24.

<7 = <8

<7 + 5y - 29 = 180°( angles on a straight line)

<7 = 180° + 29 - (5 × 24)

= 209 - 120

<7 = 89°

<8 = 89° (vertically opposite angles)