How long will it take a sum of money to triple if it is invested at
10
%
compounded daily? Round to the nearest hundredth of a year.

11.64 years

Step-by-step explanation:

A = P(1+r/n)^nt

r = interest rate in decimals

t = time in years

n = number of times compounded per year

A = future amount

P = initial amount

We are given that our money will triple so we can let A = 3x if we let P = x

r = 0.1

n = 1

then we can write

3x = x(1+(0.1/1))^1t

3x = x (1.1)^t

3 = 1.1^t (divide both sides by x)

take log of each side

log 3 = log 1.1^t

log 3 = t*log(1.1)

t = log 3 / log(1.1)

t = 11.64 years

Option B) 3.04

Step-by-step explanation:

We are given the following in the question:

Number of people interviewed,n = 163

Number of people hire, x = 121

Proportion of people hire =

Mean, μ = 3.3

Standard Deviation, σ = 0.4

We are given that the distribution of GPA for the successful interviewees is a bell shaped distribution that is a normal distribution.

Formula:

We have to find the value of x such that the probability is 0.742

Calculation the value from standard normal z table, we have,  

Thus, cut-off GPA should be 3.04.

Option B) 3.04