How many solutions would there be for the following system of equations? y = 3x - 5
62 - 2y = 10
A 1 Solution
B 2 Solutions
No solution
D Infinitely Many solutions

1 solution

Step-by-step explanation:

y = 3x-5

This is a line with a non-zero slope.

62-2y = 10

2y =  52

y = 26

This is a horizontal line.

The lines intersect at one point, (31/3, 26)

II quadrant or IV quadrant

Step-by-step explanation:

we know that

In the I quadrant

The x-coordinate and the y-coordinate are both positive

In the II quadrant

The x-coordinate is negative and the y-coordinate is positive

In the III quadrant

The x-coordinate and the y-coordinate are both negative

In the IV quadrant

The x-coordinate is positive and the y-coordinate is negative

therefore

If the coordinates of an ordered pair have opposite signs, then the ordered pair must lie in the II quadrant or in the IV quadrant