How much do you need to subtract from 63/10 to make 6

0.3

63/10 = 63 ÷ 10 = 6.3 

If we want 6 we need to subtract a number (x) from 6.3

6.3 - x = 6
-x = 6 - 6.3
-x = -0.3
x = 0.3

So we need to subtract 0.3 from 6.3 to get 6.

Since this is a simple equation we could of just looked at it and saw that we need to subtract 0.3, but later when equations get more complicated this method will work better. 

Hope this Helps! :)

Let the number be x

x - 63/10 = 6

10 x - 63 = 60

10x = 123

x = 12.3

The coordinates of the location of point B are (0 , 3) ⇒ answer A

Step-by-step explanation:

* Lets revise some facts

- In the square the diagonals bisect each other, that means they meet

 each other at their mid-point

- In square ABCD , AC and BD are its diagonal

- AC and DB intersect each other at point M where M is the midpoint of

 AC and BD

- The rule of the midpoint of the line whose endpoints are (x1 , y1) and

 (x2 , y2) is

∵ A = (-2 , 4) and C = (-1 , 1)

∵ M is the mid-point of AC

∴

- M is also the mid point of BD

∵ D = (-3 , 2) and M = (-1.5 , 2.5)

- Let B = (x , y)

∵ -1.5 = (x + -3)/2 ⇒ multiply both sides by 2

∴ -3 = x + - 3 add 3 to both sides

∴ 0 = x

∴ The x-coordinate of B is 0

∵ 2.5 = (y + 2)/2 ⇒ multiply both sides by 2

∴ 5 = y + 2 subtract 2 from both sides

∴ 3 = y

∴ The y-coordinate of B is 3

∴ B = (0 , 3)

* The coordinates of the location of point B are (0 , 3)