kaylaanndupree
27.11.2019 •
Mathematics
Iam a quantity that can change or vary, taking on different values. who am i?
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Ответ:
Ответ:
x>2
Step-by-step explanation:
x3+3x2=7x+6
x3+3x2−(7x+6)=7x+6−(7x+6)
x3+3x2−7x−6=0
(x−2)(x2+5x+3)=0
x−2=0 or x2+5x+3=0
x=2 or x=−0.6972243622680054 or x=−4.302775637731995
x<−4.302776
−4.302776<x<−0.697224
−0.697224<x<2
x>2(Works in original inequality)