jason1702
03.03.2021 •
Mathematics
If 8^y = 16^x + 2 what is the value of Y
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Ответ:
Ответ:
y= -8
Step-by-step explanation:
8^y = 16^(y+2)
//to solve make the base equal, both 8 and 16 are powers of (2
(2^3)^y = (2^4)^(y+2)
//simplify, remember when doing this multiply the powers
2^3y = 2^(4y+8)
// now we can just make the 2 powers equal
3y = 4y+8
0=y+8
y= -8
check:
8^(-8) = 16^(-6)
2^(-24) = 2^(-24)
Ответ: