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31.08.2019 •
Mathematics
If a 3x3 matrix m has characteristic equation 1lambda^3 -39lambda^2 + 5lambda = 0. what is the value of the larger non-zero eigenvalue of m? it is not required to know m exactly. give your answer to 3 decimal places
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Ответ:
38.8713
Step-by-step explanation:
We have given the a 3×3 matrix
The characteristic equation of the matrix is given by![\lambda ^3-39\lambda ^2+5\lambda =0](/tpl/images/0213/7283/5cc4d.png)
This is the property of the characteristic equation that the root of the the characteristic equation are the eigen value of the matrix
The roots of the equation
are ![\lambda =38.8713\ \lambda =0\ \lambda =0.12863](/tpl/images/0213/7283/aae55.png)
We have to find the larger non zero eigen value
So the larger non zero eigen value will be 38.8713
Ответ:
x = -20 X t-2 = C
Step-by-step explanation: