Mathematics: If m(8, 1) is the midpoint of the line segment ab, and if a has coordinates (6, −2), find the coordinates of b.

If m(8, 1) is the midpoint of the line segment ab,

leah24645

12.03.2022

The formula of a midpoint:

$M\left(\dfrac{x_1+x_2}{2};\ \dfrac{y_2-y_1}{2}\right)$

We have:

$(6,\ -2)\to x_1=6,\ y_1=-2\\\\M(8,\ 1)$

Substitute:

$\dfrac{6+x_2}{2}=8\ and\ \dfrac{-2+y_2}{2}=1$

First equation:

$\dfrac{6+x_2}{2}=8\ \ \ |\cdot2\\\\6+x_2=16\ \ \ |-6\\\\x_2=10$

Second equation:

$\dfrac{-2+y_2}{2}=1\ \ \ \ |\cdot2\\\\-2+y_2=2\ \ \ |+2\\\\y_2=4$

The coordinates of point B are (10, 4).

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bob4059

10.12.2021

-40

Step-by-step explanation:

Negative × positive = negative-5 × 8 = -40

I hope this helps!

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