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noellelovebug1214
08.01.2020 •
Mathematics
If the evaluate of a is negative and the vertex is at (13, -2) then how many x-interceps will the graph?
a) 2
b) it cannot be determined from the information
c)0
d) 1
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Ответ:
vertex is (h,k)
and when a is positive then the parabola opens up and the vertex is lowest point
so since vertex is (13,-2) then it is below the x axis (-2<0)
and since a is negative, it opens down
so the vertex is the highest point
since the highest point is already below the x axis, there cannot be any x intercepts
0 intercepts
answer is C
Ответ:
y = 4x - 12
Step-by-step explanation:
if it allows you to, i would plot the points first, draw the line with a straight edge connecting the two points, and then find the slope and y - intercept using that