If the integers a and n are greater than 1 and the product of the first 8 positive integers is a multiple of a^n, what is the value of a? (1) a^n = 64(2) n=6

a=2

Step-by-step explanation:

Well, first let us find product of the first 8 positive integers, which is 1*2*3*4*5*6*7*8=40320. It can also be written as 40320=*3²*5*7. From the formula above, it can be extracted that if a=2, n can be any number from 3 to 7 (considering that a and n are not equal and greater than 1).

In (1) a^n=64 and in (2) n=6 so it can be written as 2^6=64 so a=2 and n=6. So the value of a is 2. a=2

domain: 0 ≤ t ≤ 4

range:  0 ≤ h ≤ 19.6