Mathematics: In circle T with m ∠ S V U = 5 6 ∘ m∠SVU=56 ∘ , find the angle measure of minor arc ⌢ . SU ⌢

In circle T with m ∠ S V U = 5 6 ∘ m∠SVU=56 ∘

GingerSnaps

30.12.2020

Given:

m∠NRQ = 60°

To find:

The angle measure of minor arc NQ

Solution:

The inscribed angle is half of the intercepted arc.

$$\Rightarrow m\angle NRQ =\frac{1}{2} m(ar NQ)$

Multiply by 2 on both sides.

$$\Rightarrow 2 \times m\angle NRQ =2 \times \frac{1}{2} m(ar NQ)$

$$\Rightarrow 2 \ m\angle NRQ =m(ar NQ)$

Substitute m∠NRQ = 60°.

$$\Rightarrow 2\times 60^\circ=m(ar NQ)$

$$\Rightarrow 120^\circ=m(ar NQ)$

The measure of minor arc NQ is 120°.

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caleelwittmann31

26.09.2021

Step-by-step explanation:

Dilation from origin rule: (kx,ky) where k is the scale factor.

In this case, you would multiply each coordinate by 1.5 so, after multiplying the answer would be A.

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