In how many ways can 4 different novels, 2 different mathematics books, and 1 biology book be arranged on a bookshelf if the novels must be together but the other books can be arranged in any order?

Pt = 576

Step-by-step explanation:

If 4 different novels must be together, we have 4 elements then

P₁  = 4!       P₁  = 4*3*2*1

 P₁  =  24

But now we have to consider  position between the novel group

P₂  =  4!      P₂    =  24

Total ways

Pt  =  24*24

Pt = 576

H: 1 1/2 pt

Step-by-step explanation:

You get H because 1 pint is 16 ounces, 2 pints are 32 ounces but you need the number 24. So i did a half of 16 and 32 which is 24. So my answer is          1 1/2pt.