In how many ways can you choose a jury of 12 members from a group of 9 men and 11 women given the following conditions: a) The jury is comprised of 6 men and 6 women?
b) The jury is comprised of at most 4 men?
c) The jury is comprised of at least 7 women?

A

Step-by-step explanation:

The jury is compromised of 6 men and 6 women

1. x<3

2.x>3

Step-by-step explanation:

Number 1.

Step 1: Add 9 to both sides.

7x−9+9<12+9

7x<21

Step 2: Divide both sides by 7.

7x

7

<

21

7

x<3

Number 2.

1x+8>11

Step 1: Simplify both sides of the inequality.

x+8>11

Step 2: Subtract 8 from both sides.

x+8−8>11−8

x>3

leave alike if this help please.