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27.02.2021 •
Mathematics
In mathematics given that x=L2-L1/L1(O2-O1).
1.make L1 the subject formula
2.make O2the subject formula
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Ответ:
1. L1 =![\frac{L2}{X(O2 -O1)}](/tpl/images/1154/1562/37bad.png)
2. O2 =![\frac{L2 - L1(1 + XO1)}{XL1}](/tpl/images/1154/1562/0a585.png)
Step-by-step explanation:
Given: x =![\frac{L2 - L1}{L1(O2 -O1)}](/tpl/images/1154/1562/64e4c.png)
1. To make L1 the subject of formula;
x =![\frac{L2 - L1}{L1(O2 -O1)}](/tpl/images/1154/1562/64e4c.png)
cross multiply to have;
L2 - L1 = xL1(O2 - O1)
collect like terms,
L2 = xL1(O2 - O1) + L1
factorize the right hand side;
L2 = L1[x(O2 - O1)]
L1 =![\frac{L2}{X(O2 -O1)}](/tpl/images/1154/1562/37bad.png)
2. To make O2 the subject of formula;
x =![\frac{L2 - L1}{L1(O2 -O1)}](/tpl/images/1154/1562/64e4c.png)
cross multiply to have;
L2 - L1 = xL1(O2 - O1)
open the bracket to have;
L2 - L1 = xL1O2 - xL1O1
⇒ xL1O2 = L2 - L1 + xL1O1
O2 =![\frac{L2-L1 + XL1O1}{XL1}](/tpl/images/1154/1562/620c3.png)
=![\frac{L2 - L1(1 + XO1)}{XL1}](/tpl/images/1154/1562/0a585.png)
Ответ: