In the fig given below .AB║DC find x
helpplzzz

x = 150°

Step-by-step explanation:

The given parameters are;

AB ║ DC

∠BAE = 105°

∠AEC = 25°

We construct a line CF from C parallel to the line AE as presented in the included diagram created with Microsoft Visio

We have;

∠DCF ≅ ∠BAE = 105° by similar angles formed by two pairs of parallel lines

∠AEC = ∠ECF = 25° by alternate interior angles formed by two parallel lines and a common transversal

x = 125° + 25° = 150° By angle addition postulate

x = 150°.

98 ° is measures angle x.Hope this helps you.