in the figure, one side of the rectangle divides the circle in half.
what is the area of the unshaded portion of the figure?

use 3.14 to approximate for π

enter your answer to the nearest tenth in the box.

For a better understanding of the solution given here please go through the diagram in the file attached. Let the area of the triangle ABC be denoted by the letter "a". We know that since D is the midpoint of AB then CD must be a median and we know that a median divides the area of any triangle in half. Thus, from the figure, Area of ….(Equation 1)Now, in  DE is the median and thus, Area of …(Equation 2)Again, in , DF is the median, so, area of …….(Equation 3)As, we can see, the area of the given triangle,  which is the sum of shaded areas depicted by "x" and "y". Now, this area is obviously, the sum of the area of (Equation 2) and (Equation 3). Thus we have: Solving, we get: sq. cm