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sxbenn
31.07.2020 •
Mathematics
In the lab, Goran has two solutions that contain alcohol and is mixing them with each other. Solution A is 40% alcohol and Solution B is 10% alcohol. He uses 800 milliliters of Solution A. How many milliliters of Solution B does he use, if the resulting mixture is a 30% alcohol solution?
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Ответ:
400milliliters
Step-by-step explanation:
Let x=ml of 30% solution B used in resulting mixture.
800+x=ml of resulting 30% solution
40%(800)+10%x=30%(800+x)
Then we can simplify the expression
0.4(800)+0.10x= 0.30(800+x)
320+0.10x=240+0.30x
80=0.20x
x= 400milliliters
Therefore, 400milliliters of 10% solution B used in resulting mixture.
Ответ:
hope this helps :)