In triangle abc the measure of angle a is 5 degrees more that 3 times the measure of angle b . angle c measures 20 degrees less than angle b . determine the measures of angle a b and c

Measures of angles are equal to respectively.

According to the angle sum property of a triangle, sum of all the angles of a triangle is equal to

Let measure of angle be

Measure of angle

Measure of angle

So,

Measure of angle

Measure of angle

Measure of angle

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a = 122°, b = 39° and c = 19°

angle a = 3b + 5 and angle c = b - 20

The sum of the angles in a triangle = 180°

Thus 3b + 5 + b + b - 20 = 180 ( solve for b)

5b - 15 = 180

add 15 to both sides

5b = 180 + 15 = 195

divide both sides by 5

b = = 39

angles are a = ( 3 × 39) + 5 = 122°, b = 39°, c = 39 - 20 = 19°

Idk, I don’t read ancient egyptian