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bobtothemaxthe1st
07.05.2021 •
Mathematics
Is f(x)= 7e^-21 an example of exponential growth or decay?
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Ответ:
Ответ:
(1)
Probability that all are yellow =![\frac{7\times6\times5\times4\times3}{16\times15\times14\times13\times12}=0.0048](/tpl/images/0079/3481/d83b0.png)
Probability that all are orange =![\frac{9\times8\times7\times6\times5}{16\times15\times14\times13\times12}=0.0288](/tpl/images/0079/3481/69932.png)
Sum of the two probabilities = 0048+ 0.0288=0.0336
Thus, the probability that at least one is orange and at least one is yellow = 1-0.0336= 0.9664= 96.64 %
(2) In addition to the above, we eliminate the "1 and 4" cases.
In these cases, any of the 5 can be taken out, so we multiply by 5.
1 yellow + 4 orange =![5\times \frac{(7 \times 9 \times 8 \times 7 \times 6)}{(16 \times 15 \times 14 \times 13 \times12)} = 0.2019](/tpl/images/0079/3481/b4b7f.png)
1 orange + 4 yellow =![5 \times \frac{(9 \times 7\times 6 \times 5 \times 4)}{(16 \times 15\times 14 \times 13 \times 12)} = 0.0721](/tpl/images/0079/3481/2500e.png)
Sum of two probabilities = 0.2019+0.0721=0.2740
Now adding 0.0336 to this probability =0.0336+0.2740= 0.3076
Subtracting that from 1.0000 = 1-0.3076=0.6924= 69.24 %
Thus, the probability that, of the 5 balls selected at random, at least two are orange and at least two are yellow= 69.24%