Is the first question correct ? and need with the rest

Yes, your 1st question is right. i double checked it.The answer to number 1 is shorter.Number 2 is no Megan's pencil is shortet than Kims pencil. the 3rd answer you have to draw 3 lines that are not the same length. (ill show you one)
as you see the 3 lines they are not the same length. Im sorry but i don't know what to write for a sentence but I'll try if I'm wrong please forgive me. i think you write: the first line is longer than the second line but the second line is longer than the third line but the 3rd line is shorter than the 2nd line and 3rd line. Hope this helps! (: (i tried my best to help you)

Answers and Step-by-step explanations:

A.

One pair of similar triangles are ΔGBC and ΔEBP.

B.

∠GBC and ∠EBP are vertical angles, so by definition, they are congruent. We also know that since GRPC is a parallelogram, then opposite sides are parallel, so GC ║ RE. Then, since GE is a transversal of these two lines, ∠CGB and ∠PEB are alternate interior angles. By definition, they are congruent.

Thus, by the Angle-Angle Similarity Theorem, ΔGBC ~ ΔEBP.

C.

Similar triangles have the property that corresponding sides have the same ratio. Here, GB corresponds to EB, BC corresponds with BP, and GC corresponds to EP.

We know that BC / BP = 350 / 250. So, this ratio is equivalent to GB / EB and GC / EP:

GB/EB = GC/EP = 350/250

GB = 450 and GC = 400, so:

450/EB = 400/EP = 350/250

Solve for EB and EP separately:

450/EB = 350/250

350EB = 112500

EB = 2250/7 ft

400/EP = 350/250

350EP = 100000

EP = 2000/7 ft