Jenny is 6b years old. her brother is half her age and her sister is 4 years older than jenny. what is the average age of the three siblings in terms of b?

5b + 4/3

Step-by-step explanation:

So if Jenny is 6b and her brother is half that he must be 3b. If her sister is four years older than her then she must be 6b + 4. To find the mean (or average) you add all the numbers and then divide by how ever many things you added together, so you would do:

Average = (6b+3b+6b+4) ÷ 3

= (15b+4) ÷ 3

= 5b + 4/3

t=60

Step-by-step explanation:

3/2t-16=4/3t-6

(subtract 4/3t from both sides)

3/2t-16-4/3t=-6

(add 16 to both sides)

3/2t-4/3t=-6+16

(simplify)

1/6t=10

(divide by 1/6 (or multiply by 6 on both sides)

t=60