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dianepowers1
22.11.2019 •
Mathematics
Let logb a= 3; logb c = 2; logb d=5
what is the value of logb d^2/c^3a
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Ответ:
The value of given log function is 1 .
Step-by-step explanation:
Given as :
Logb A = 3
Logb C = 2
Logb D = 5
Now from log property
if , Logb x = c , then x =![b^{c}](/tpl/images/0385/5090/fbee0.png)
So,
Logb A = 3 , then A =![b^{3}](/tpl/images/0385/5090/7c4e1.png)
Logb C = 2 , then C =![b^{2}](/tpl/images/0385/5090/0ed44.png)
Logb D = 5 , then D =![b^{5}](/tpl/images/0385/5090/67f35.png)
Now, According to question
So,![Logb\frac{(b^{5})^{2}}{(b^{2})^{3}\times b^{3}}](/tpl/images/0385/5090/a7a23.png)
Or,![Logb\frac{b^{10}}{b^{6}\times b^{3}}](/tpl/images/0385/5090/c8ae1.png)
or,![Logb\frac{b^{10}}{b^{9}}](/tpl/images/0385/5090/e9865.png)
Now, since base same So,
∴![log_{b}b^{1}](/tpl/images/0385/5090/a2c1c.png)
Now log property
Hence The value of given log function is 1 . answer
Ответ:
390.8048
Step-by-step explanation:
Just use a calculator next time lol it will be easier