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Giabear23
19.12.2019 •
Mathematics
Maria invested a total of 31,000 in two account, first account earned a rate of 14%. how ever second account suffer a 10% loss in the same time. at the end of one year the total amount money gain 1,700. how much was invested in school account
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Ответ:
the amount of money that Maria invested in the first account is $20000
the amount of money that Maria invested in the second account is $11000
Step-by-step explanation:
Let x represent the amount of money that Maria invested in the first account.
Let y represent the amount of money that Maria invested in the second account.
Maria invested a total of 31,000 in the two account. This means that
x + y = 31000
The first account earned a rate of 14%. This means that the amount earned on the first account is 14/100×x = 0.14x
However, the second account suffered a 10% loss in the same time. This means that the amount lost is
10/100×y = 0.1y
At the end of one year the total amount money gain 1,700. This means that
0.14x - 0.1y = 1700 - - - - --1
Substituting x = 31000 - y into equation 1, it becomes
0.14(31000 - y)- 0.1y = 1700
4340 - 0.14y - 0.1y = 1700
- 0.14y - 0.1y = 1700 - 4340
-0.24y = -2640
y = 2640/0.24 = 11000
x = 31000 - y = 31000 - 11000
x = 20000
Ответ:
sorry idk
step-by-step explanation: