Mathematics: Math geometry question 4, Thanks if you help

Math geometry question 4, Thanks if you help

dreamdancekay

22.01.2022

JDK-right triangle. JD=13, DK=3

By the Pythagorean theorem

$13^2+3^2=JK^2\\JK=\sqrt{169+9} \\JK=\sqrt{178} \\$

JK≈13,34

the distance is 13 units

P.S. Hello from Russia

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laiahlott

22.01.2022

The distance between two points J and K is 13 unit (approx)

Step-by-step explanation:

Given,

Two points are J(3,0) and k(6,-13).

To find the distance between J and K.

Formula

The distance between two points ( $x_{1} ,y_{1}$ ) and ( $x_{2} ,y_{2}$ ) is $\sqrt{(x_{2}-x_{1} ) ^{2}+(y_{2}-y_{1} ) ^{2} }$

Now,

Putting, $x_{1} = 3, y_{1}=0, x_{2}=6, y_{2}=-13$ we get,

JK = $\sqrt{(6-3)^{2} +(-13-0)^{2} }$

= $\sqrt{178}$ unit = 13.34 unit (approx)

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honeyaranda326pay2bl

03.05.2023

The two pink or Rose colored ones are parallelograms

Step-by-step explanation:

They both have lines that are one pair of parallel lines to each other

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