Mr. lance keeps a jar of candy on his desk for students to pick from when they do well on a test. the jar contains 5 snickers, 2 butterfingers, 4 almond joys and 3 milky ways. if two students get to pick candy from the jar, what is the probability that the first student picks a snickers and then the second student also picks a snickers?

Step-by-step explanation:

Given : The jar contains 5 Snickers, 2 Butterfingers, 4 Almond Joys and 3 Milky Ways.

Total candies in the jar =

Provability that firsts student select snickers =

Now total candies in jar = 14-1=13

Total snickers remained =5-1=4

Probability that the second student also select snickers=

Then, the probability that the first student picks a Snickers and then the second student also picks a Snickers :-

Hence, the required probability =

Step-by-step explanation:

Solve by Elimination

eliminate 12

8x=42

divide 8 on both sides

x=5.25

Now solve for y

plug in y for either equation, I plugged in 5.25 in the first equation

3(5.25)-12=14

× =

15.75-12=14

add 12 on both sides

15.75....

This is how far I got, I just realized that your question doesnt have a y variable, therefore this is not a system of equation.