Mathematics: Multiply.1. 2. 3. 3y²(y²-2y+3) 4. (x + 3)(x-2)

Multiply.1. 2. 3. 3y²(y²-2y+3) 4. (x + 3)(x-2) - id1233234321839540, sierradanielle9280

Ответ:

noahdeem135

31.12.2021

$1. \\ \\(2x^3y^3)(5x^2y^8) =2\cdot 5\cdot x^{3+2}\cdot y^{3+8} =10 \cdot x^{5}\cdot y^{11} \\ \\ 2.\\ \\ 9b^3(8b^4)(-b) =-9\cdot 8\cdot b^{3+4+1} =-72\cdot b^{8}$

$3.\\ \\ 3y^2(y^2-2y+3)=\\ \\=3y^2\cdot y^2-3y^2\cdot 2y+3y^2\cdot 3 =\\ \\ =3y ^{2+2} -6y ^{2+1} +9y^2 =\\ \\= 3y ^{4} -6y ^{3} +9y^2$

$4.\\ \\ (x + 3)(x-2)=x^2-2x+3x-6 = x^2+x-6$

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Ответ:

bri9263

10.05.2021

Mathematics

Step-by-step explanation:

1. 21/100

2. 9/100

3. 49/100

hope this helps

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Multiply.
1. 2.
3. 3y²(y²-2y+3) 4. (x + 3)(x-2)

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