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18.06.2020 •
Mathematics
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Ответ:
47.5% of students fall within heights of 100 cm to 120 cm
Step-by-step explanation:
We are given that heights of Grade 1 students are normally distributed
Mean =![\mu = 100 cm](/tpl/images/0688/9491/542e3.png)
Standard deviation =![\sigma = 10 cm](/tpl/images/0688/9491/46bff.png)
a)
Empirical rule
68% of data lies within the first standard deviation from the mean i.e![.(\mu-\sigma , \mu+\sigma)=(100-10,100+10)=(90,110)](/tpl/images/0688/9491/478ee.png)
95% of all the data will fall within two standard deviations i.e.![(\mu-2\sigma , \mu+2\sigma)=(100-2(10),100+2(10))=(80,120)](/tpl/images/0688/9491/b53ea.png)
99.7% of data lies within the three standard deviations i.e.![( \mu - 3 \sigma , \mu +3 \sigma)=(100-3(10),100+3(10))=(70,130)](/tpl/images/0688/9491/d6c58.png)
b)Percentage of students fall within heights of 100 cm to 120 cm
Using the normal distribution curve
Percentage of students fall within heights of 100 cm to 120 cm =![\frac{1}{2} \times 95\% = 47.5\%](/tpl/images/0688/9491/2804a.png)
Hence 47.5% of students fall within heights of 100 cm to 120 cm
Ответ: