abebaretosuacegod445
15.11.2021 •
Mathematics
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Ответ:
Ответ:
Ответ:
Tangent²=(The whole secant segment)(External secant segment)
2. The whole secant segment is: AD=a+12
3. The external secant segment is: BD=10
4. The tangent segment is: DE=12
5. Then, you have:
DE²=ADxBD
12²=(a+10)10
10(a+10)=12²
6. Therefore, the answer is the third option: 10(a+10)=12²