Parallelogram PQRS has diagonals PR and SQ that intersersect at T find the values of x and y PT=y TR=3x+1 QT=3y TS=4x+13

Hence x = 2 and y = 7

Step-by-step explanation:

If a parallelogram PQRS has diagonals PR and SQ that intersects at T, then;

T is the midpoint of PR and T is the midpoint of SQ

If T is the midpoint of PR, then PT = TR

Given  PT=y and TR=3x+1

y = 3x+ 1 1

Also, If T is the midpoint of SQ, then ST = TQ

Given QT=3y and TS=4x+13

3y = 4x+ 13 2

Substitute equation 1 into 2;

3y = 4x+ 13

3(3x+1) = 4x+ 13

open the parenthesis

9x+3 = 4x+13

collect like terms

9x-4x = 13-3

5x = 10

x = 10/5

x = 2

Substitute x = 2 into equation 1

From 1; y = 3x+1

y = 3(2)+1

y = 6+1

y = 7

Hence x = 2 and y = 7

3^2x

Step-by-step explanation: