Please HELp
How do u solve dis.

Step-by-step explanation:

x+77=126 (vertical opposite angles are equal)

x=126-77

x= 49

The z-score corresponding to the weight 169 oz is -1.4

Using the table, the percentage associated with this z-score is 41.92%

The z-score corresponding to the weight 191 oz is 1.4

Using the table, the percentage associated with this z-score is 41.92%

The percentage between 169 oz. and 191 oz. is 83.84%

Step-by-step explanation:

We are informed that the weights of vegetables in a field are normally distributed with the following characteristics;

Mean weight = 180

Standard deviation = 8

We are to determine the percent of the vegetable boxes grouped for sale with a weight between 169 oz. and 191 oz. To do this, we shall perform a number of calculations involving z-cores;

The first step is to compute the z-score corresponding to the weight of 169 oz;

Using the table, the percentage associated with this z-score is 41.92% since the standard normal curve is symmetric.

The next step is to compute the z-score corresponding to the weight of 191 oz;

Using the table, the percentage associated with this z-score is 41.92%

Finally, the percentage between 169 oz. and 191 oz. is;

41.92% + 41.92% = 83.84%.