PLEASE HELP!! If f (x) = x^3 - x^2 + x - 1, then f’(2) =

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Work Shown:

f(x) = x^3 - x^2 + x - 1

f ' (x) = 3x^2 - 2x + 1

f ' (2) = 3(2)^2 - 2(2) + 1

f ' (2) = 9

In step 2, I used the power rule

Step-by-step explanation:

we know that

The area of the figure is equal to the area of a triangle plus the area of a parallelogram

Find the area of triangle KLM

we have

--> difference of the x-coordinates points M and K

--> difference of the y-coordinates points L and K

substitute

Find the area of parallelogram JKMN

--> difference of the x-coordinates points N and J

--> difference of the y-coordinates points K and J

substitute

The area of the figure is equal to