PLZ HELP! Joel rolls two fair number cubes at the same time. What is the probability that the sum of the numbers will be odd or less than 4? Show your work.

Joel rolls two fair number cubes at the same time.

Each cube has six sides 1, 2, 3, 4, 5, 6

=> There are 6 x 6 = 36 possible pairs (or 36 possible sums)

The collection of pairs that have sum less than 4 includes (1, 2), (2, 1) and (1, 1) => 3 cases (*)

The sum that is odd when two cubes show one odd number and one even number. Therefore each side of first cube has 3 options from second cube to form an odd sum. => The total number of cases: 6 x 3 = 18  cases

In these 18 cases, there are two cases (1, 2) and (2, 1) which have been counted already at (*) => Total case that the sum of the numbers will be odd or less than 4: T = 3 + 18 - 2 = 19 cases

=> Probability that the sum of the numbers will be odd or less than 4:

P = 19/36 = 0.53

Hope this helps!

:)

Approximately 268.33

Step-by-step explanation:

First, we need to find the scale factor of the map. We can do so by taking the width of Indiana and dividing it by the width of the map.

This shows us that the scale factor of the map is 23.333 miles per inch.

Then, we need to multiply the length of the map by the scale factor. The map is 11.5 inches long and the scale factor is 23.333 miles per inch.