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12.07.2019 •
Mathematics
Point a pq and r are collinear on pr and pq: pr =2/3. p is located on the origin q is located at (x,y) and r is located at (-12,0) . what are the values of x and y
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Ответ:
The values of x and y are 8 and 0 respectively.
Explanation
As 'p' is located at (0,0) and 'r' is located at (-12,0) , that means both 'p' and 'r' are on the x-axis. So point 'q' will be also on the x-axis , and 'q' is located at (x,y)
So, the value of y will be 0. That means the co ordinate of point 'q' is (x, 0)
Now, using the Distance formula, length of 'pq'
and length of 'pr'
Given that, pq : pr =2/3
So....
Thus, the values of x and y are 8 and 0 respectively.
Ответ:
$37
Step-by-step explanation:
-$17+-$20