Problem: a circle is inscribed in a square. the squares perimeter is 16 times the square root of 6. what is the probability of selecting a point that is outside the circle? ?
• explain and show steps in detail on how to solve for the correct answer

I got 21% at selecting a point outside.
Explanation: Since the perimeter is 16sqrt (6), each side must be 4sqrt (6)
This also means that the diameter is 4sqrt (6).

To find the area of a circle, we need to find the radius (2sqrt (6)).
Area of circle is pi × (2sqrt (6))^2 = 24pi or approximately 75.4 units^2
Area of square is 4sqrt (6)^2 = 96

Thus, let's take the area of the circle and subtract that from the area of our square to yield approx. 20.6 units^2
and now divide through by 96 to yield 21%

The equivalent ratio to 1:5 is 2:10,3:15,4:20, etc.

Given that,

We need to find the equivalent ratio to 1:5.

Here the equivalent ratio could be determined by measuring the common factor.

Like 2:10 = 1:5

3:15 = 1:5

4:20 = 1:5

Therefore we can conclude that the equivalent ratio to 1:5 is 2:10,3:15,4:20, etc.

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