emmagossett2002
30.10.2019 •
Mathematics
Prove: every point on the perpendicular bisector of a segment is equidistant from the ends of the segment.
ap = bp
(fill in the blanks of the equation in the second picture with the correct number/letter/sign based off the first picture.)
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Ответ:
Answer with explanation:
Here ,let line, x=0 intersect ,segment AB at point M.
So, PM ⊥ AB.
And, AM =BM →→→∵ y axis or segment PM , is Perpendicular bisector of segment AB.
In Δ AMP and ΔB MP
∠AMP = ∠ B MP=90°[→→ Each being 90°]
AM = BM →Line PM , is perpendicular Bisector.
Side MP , is Common.
Δ AMP ≅ ΔB MP→→→[S AS]
So, AP= BP →→[C P C T]
2. We will use distance formula to find AP and BP.
Distance between two points is given by
Hence, AP = BP
Where ,Point P, can be located anywhere on y axis.
Ответ: