Mathematics: Prove that the square of any odd integer is of the form 8n+1

Prove that the square of any odd integer is of the

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bayloann2621

03.08.2019

For any integer x, if x is even, then x^2+x = (2k)^2 +2k =2(2k^2 +k) is evenif x is odd, thenx^2+x =(2k+1)^2 +2k+1 = 2(2k^2 +3k +1) is also even.when x is odd, x^2 = (2k+1)^2 =4(k^2+k)+1 = 4(2n)+1 =8n+1

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Ответ:

oomale

06.07.2020

Mathematics

8 sin 35° the answer for it

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Prove that the square of any odd integer is of the form 8n+1

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