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dman09082000
14.01.2020 •
Mathematics
Pumping alone at respective constant one inlet pipe fills an empty tank to 1/2 of capacity in 3 hours and a second inlet pipe fills the same empty tank to 2/3 of capacity in 6 hours.
how many hours will it take both pipes, pumping simultaneously at their respective constant rates, to fill the empty tank to capacity?
a. 3.25
b. 3.6
c. 4.2
d. 4.4
e. 5.5
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Ответ:
B. 3.6
Step-by-step explanation:
Given : Time taken by one inlet pipe to empty
of tank = 3 hours
⇒ Time taken by one inlet pipe to empty tank (entire) = 2 x 3 hours
= 6 hours →![t_1](/tpl/images/0454/7660/9e33e.png)
Time taken by second inlet pipe to empty
of tank = 6 hours
⇒ Time taken by second inlet pipe to empty tank (entire) =![\dfrac{3}{2}\times6= 3\times6](/tpl/images/0454/7660/cc607.png)
= 9 hours →![t_2](/tpl/images/0454/7660/1dcdf.png)
If both pipes are pumping simultaneously at their respective constant rates to fill the empty tank to capacity.
Then time taken by them to fill the empty tank to capacity would be![\dfrac{t_1t_2}{t_1+t_2}](/tpl/images/0454/7660/4d9bf.png)
Hence, it will take 3.6 hours to fill the empty tank to capacity .
Therefore , the correct answer is B. 3.6 .
Ответ:
good wbu
Step-by-step explanation: