connienash95
19.11.2020 •
Mathematics
QR⟂RS, ∠QSR≅∠SQT, and ST⟂QT. Complete the proof that △QRS≅△STQ.
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Ответ:
y = 4x - 2z
Step-by-step explanation:
8x - 2y = 4z
-8x -8x
-2y = -8x + 4z
/-2 /-2 /-2
y = 4x - 2z
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