Quadrilateral DEFG has vertices at D(3,4) E(8,6) F(9,9) G(4,7). Prove that DGEF is a parallelogram

Sorry I’m kinda lazy to graph it but here are the ways you can prove a parallelogram:
Both pairs of opposite sides are parallel.
Both pairs of opposite sides are congruent.
Both pairs of opposite angles are congruent.
Diagonals bisect each other.
One angle is supplementary to both consecutive angles (same-side interior)

The answer would be D.

You would do z^2-y^2 then square root it!