Quadrilateral rstu has vertices r (-3, 1) , s (-2, 3) , t (2, 3) , and u (3, 1). if you translate the quadrilateral four units down, what are the vertices of r's't'u'? r' (-3, -3) , s' (-2, -1) , t '(2, -1) , and u' (3, -3) r' (1, 1) , s' (2, 3) , t '(6, 3) , and u '(7, 1) r' (-7, 1) , s' (-6, 3) , t '(-2, 3) , and u '(-1, 1) r (-3, 3) , s (-2, 1) , t (2, 1) , and u (3, 3) @squirrels @tkhunny,

First option

Explanation:
Translating a point four units downwards means that:
the x-coordinate would stay the same
the y coordinate will be decreased by 4

Now, for the given points:
Point R (-3,1)
x coordinate o R' = x coordinate of R = -3
y cordinate of R' = y coordinate of R - 4 = 1 - 4 = -3
R' is (-3 , -3)

Point S (-2,3)
x coordinate of S' = x coordinate of S = -2
y coordinate of S' = y coordinate of S - 4 = 3 - 4 = -1
S' is (-2 , -1)

Point T (2,3)
x coordinate of T' = x coordinate of T = 2
y coordinate of T' = y coordinate of T - 4 = 3 - 4 = -1
T' is (2 , -1)

Point U (3,1)
x coordinate of U' = x coordinate of U = 3
y coordinate of U' = y coordinate of U - 4 = 1 - 4 = -3
U' is (3 , -3)

Comparing the calculated values with the given ones, we will find that the correct choice is the first one.

Hope this helps :)

I think the answer is 65 degrees..hope it helps