Realize the following operations in order for the response to be in a+bi:

(7i-1)/5

Step-by-step explanation:

(4+2i)/(1-3i)

the opposite of 1-3i is 1+3i

multiply that

[(4+2i)(1+3i)]/[(1-3i)(1+3i)]

=[(4+2i+12i+6i^2)]/[(1-3i+3i-9i^2)]

=[(4+14i+6(-1))]/[(1-9(-1))]

=(4+14i-6)/(1+9)

=(-2+14i)/10

factor out the 2,

[-2(1-7i)]/10

-(1-7i)/5

(-1+7i)/5

(7i-1)/5

Remember that i^2=-1, because sqrt(-1)*sqrt(-1)=-1.