repartir 140 quetzales entre A,B y C de modo que la parte de B se a la mitad de la A y el cuarto de la C

11 boxes of cards for $72

Step-by-step explanation:

Brennan's equation would be

y=6x+6

Gabriel's Equation would be

y=5x+17

when they spend the same amount the equations will be equal

6x+6=5x+17

x+6= 11

x=11

so 11 boxes they would spend the same

To figure out cost, put 11 into the first equations

y=6(11)+6= 66+6= 72

y=5(11)+17= 55+17 = 72

so they each spent $72